Program : To check if Array contains an specific element. (Primitive value)

Using custom method

Following is the Java code to check if your array contains any specific element.

public class ArrayContains {
	
      public static void main(String args[]){
                int[] myIntArray = {43,32,53,23,12,34,3,12,43,32};
                int number = 326;
                if(contains(myIntArray,number)){
                     System.out.println("Number "+number+" is present in array.");
                }else{
                     System.out.println("Number "+number+" not found in array.");
                }
       }
	
       public static boolean contains(int[] intArray, int number){
               for(int i = 0; i < intArray.length; i++){
                   if(intArray[i] == number){
                      return true;
                    }
                }
            return false;
      }
}

Method contains returns true if the element is found and returns false if the element is not found. The above code does not use library method to find the element.

Using java.util.Arrays package

There is another fast approach to solve this using binarySearch method that is available in java.util.Arrays package

import java.util.Arrays;

public class ArrayContains {
	
        public static void main(String args[]){
             int[] myIntArray = {43,32,53,23,12,34,3,12,43,32};
             int number = 362;
             Arrays.sort(myIntArray);
             if(Arrays.binarySearch(myIntArray, number) >= 0){
                 System.out.println("Number "+number+" is present in array.");
             }else{
                 System.out.println("Number "+number+" not found in array.");
             }
        }
}

We have used the predefined library method binarySearch to check if the element exists in the Array. Notice that for binarySearch to work, the array needs to sorted and therefore we have called sort method before performing the search. binarySearch returns the index of element in the Array if the element is found. If not it will return the (-(insertion point) – 1) index of element we are searching.

Using org.apache.commons.lang3.ArrayUtils package

import org.apache.commons.lang3.ArrayUtils;

public class ArrayContains {
	
        public static void main(String args[]){
            int[] myIntArray = {43,32,53,23,12,34,3,12,43,32};
            int number = 362;
            if(ArrayUtils.contains(myIntArray,number)){
                System.out.println("Number "+number+" is present in array.");
            }else{
                System.out.println("Number "+number+" not found in array.");
            }
      }
}